solve this question plz plz plz plz
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https://youtu.be/MEol99ohgWk In the figure AB represent the height of mountain. In ∆oce , sin30° = CE/OC 1/2 = CE/1000 So, CE=500. Again, Cos30° = OE/OC ✓3/2 = OE/1000 So, OE = 500√3. In ∆AOB, Tan45° = AB/OA So AB=OA Hence, CD=EA=OA-OE = h-500√3. BD=AB-AD=AB-CE=h-500. In∆BCD,. Tan60° = BD/CD √3 = h-500/h-500√3 So.... H = 1366 m = 1.366km
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