Question

Solve this question plz
QUADRATIC EQUATIONS. ​

Answer 1

$\frac{(6x - 5)}{(x + 5)} = \frac{x}{3} - 5 \\ \frac{(6x - 5)}{(x + 5)} = \frac{x - 15}{ 3} \\ 3(6x - 5) = (x - 15)(x + 5)$

$18x - 15 = {x}^{2} + 5x - 15x - 75 \\ {x}^{2} - 10x - 18x - 75 + 15 = 0 \\ {x}^{2} - 28x - 60 = 0$

Now by using middle term splitting,

${x}^{2} - (30 - 2)x - 60 = 0 \\ {x}^{2} - 30x + 2x - 60 = 0 \\ x(x - 30) + 2(x - 30) = 0 \\ (x - 30)(x + 2)$

Therefore, The factors are (x+30) (x+2).