Question

Solve this question quickly. The question is above. ​

Answer 1

Step-by-step explanation:

AB=√(x+2)^2-x^2=√4x+4=2√x+1

cot(phai)=x/2√x+1)

(√x+1)cot(phai)=x/2

ii)tan(theta)=x/2√x+1

tan(theta)=x*x/2*x√x+1

tan(theta)=x^2/2√x^3+x^2

(√x^3+x^2)tan(theta)=x^2/2

iii)cos(theta)=2√x+1/x+2