Question

Solve this question right now plz guy's

class9​

Answer 1

Answer:

ok see the steps

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

2y^3 + y^2 - 2y - 1

y= 1

y-1= 0

divide y-1 by 2y^3 +y^2 -2y -1  =  2y^2 + 3y + 1

Divident = D X Q + R

= (y-1) (2y^2 + 3y + 1)

= (y-1) (2y^2 + 2y + y + 1)

= (y-1) [2y (y+1) + 1 (y+1)]

= (y-1) (2y+1) (y+1)