Question

Solve this question.
See the figure.. ​

Answer 1

Hello ..

Let X be acetic acid.[CH3COOH]

Acetic acid reacts with sodium to liberate H2

the reaction is as follows:

CH3COOH +Na -----> CH3COONa +H2

It reacts with NaHCO3 to liberate CO2

The reaction is as follows:

CH3COOH +NaHCO3 ----> CH3COONa+ CO2

Element Y undergoes Hydrolysis with NaoH to form Carboxylic acid salt . It means Y is an Ester.[Methyl Methanoate.]

The reaction is as follows:

HCOOCH3+ NaOH---->HCOONa +CH3OH

Therefore, Compound Z is Methanol

Hope it helps..♡