Solve this question : Sin²π÷4+cos²π÷4
Anonymous:
(sin x)^2+ (cos x)^2 is Always equal to 1
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Answer: 1
Step-by-step explanation:
sin^2 pi/4 + sin^2 pi/4
= sin^2 45 + sin^2 45
= (1/_/2)^2+(1/_/2)^2
= 1/2 + 1/2
= 1
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Answered by
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sin^2 teta/4 +cos^2 teta/4
=sin square teta +cos square teta×1/4
sin^2π + cos^2π /4
(sine square teta + cos square teta =1)
=1×1/4
=1/4
=0.25
=sin square teta +cos square teta×1/4
sin^2π + cos^2π /4
(sine square teta + cos square teta =1)
=1×1/4
=1/4
=0.25
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