Math, asked by manm90343, 20 days ago

solve this question,,, sir.. ​

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Answered by ShreyanshuGulkari
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Question

In △ABC,(b2−c2)cotA+(c2−a2)cotB+(a2−b2)cotC=

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Solution

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REF. Image.

Given

to solve the equation

(b2−c2)cotA+(c2−a2)cotB+(a2−b2)cotC.

Let us consider properties of triangle in

triagonometry. as per that we know,

⇒asinA=bsinB=csinC=K [ where 'K' is constant]

∴  sin A = ak, sin B = bk, sin C = ck. 

and also we know that,

cosA=2bcb2+c2−a2,cosB=2acc2+a2−b2,cosC=2aba2+b

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