Question

solve this question solve this question answer is 3(2a-3)(2a+3)​

Answer 1

Answer :-

$12a^{2}-27$

$=>3$ × $4a^{2}-3$ × $9$

$=>3(4a^{2}-9)$

$=>3[(2a)^{2}-3^{2}]$

$=>3[(2a+3)(2a-3)]$

Hope it Helps

Answer 2

Question:

Factorize:

12a² - 27

Answer:

➙ 3 ( 2a + 3 ) ( 2a - 3 )

Step-by-step explanation:

➙ 12a² - 27

Factorisation by taking out common factors:

• Find by inspection, the largest monomial that will divide each term of the given polynomial completely.
• Divide each term of the given polynomial by this monomial (factor) and enclose the question within the brackets keeping this common monomial outside the bracket.

⚘ By inspection, the largest monomial which divides each term of the given polynomial 12a² - 27 is 3.

➙ 3 ( 4a² - 9 )

Now, we know that 2 × 2 = 4 i.e, 2² = 4. Also, 3 × 3 = 9 i.e, 3² = 9. So it can be written as

➙ 3 ( ( 2a )² - ( 3 )² )

Factorization of difference of two squares:

• Difference of squares of two terms = Sum of two terms × their difference
• ( x + y ) ( x - y ) = x² - y²

➙ 3 ( 2a + 3 ) ( 2a - 3 )

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