Math, asked by MADHII, 6 months ago

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Answered by Anonymous
1

hope this helps

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Answered by shahom0306
1

Answer:

By similarly

Step-by-step explanation:

In triangle ABC and Triangle AMP,

AngleBAC = Angle MAP. common angle

AngleABC = able AMP.. EACH 90°

hence, angle ABC ~ Angle AMP by AA

AC/PA=BC/MP

hence, by cross multiple,

CA×MP=PA×BC

hence proved.

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