Question

Solve this question (step by step) and get 15 points :)​

Answer 1

Answer:

$\frac{16x^2+0.30y^2-4xy-0.05y^2}{4x-y+0.5y}$

$\frac{0.25y^2-4xy+16x^2}{4x-0.5y}$     (Subtracting and Adding Like Terms)

$\frac{\left(4x-0.5y\right)\left(4x-0.5y\right)}{\left(4x-0.5y\right)}$    (Factorizing The Numerator)

$4x-0.5y$                (Cancelling Like Terms)