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Step-by-step explanation:
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Lines of the Quadrilateral = AB and DC (Given)
∠FBC=90° ( As angle in the semi circle is 90°)
Similarly,
∠FGC=90°
Therefore,
∠FBC+∠FGC = 90°+90° = 180°
Hence, FBCG is a cyclic quadrilteral.
Similarly, DEGC is a cyclic quadrilteral.
∠FGC+∠EGC = 180°−∠FBE + 180°−∠EDF
Since, FBGC and DEGC are cyclic quadrilateral, thus
∠ABE + ∠ADF =180° ( Linear Pair)
Hence, FGE is straight line
HOPE IT HELPS..
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