Question

solve this question step by step fast pls
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Answer 1

Answer:

Step-by-step explanation:

$(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\{5\dfrac{1}{3}-(3-2\dfrac{1}{2})\}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\{5\dfrac{1}{3}-(3-\dfrac{5}{2})\}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\{5\dfrac{1}{3}-(\dfrac{6-5}{2})\}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\{\dfrac{16}{3}-(\dfrac{1}{2})\}]$

$=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\{\dfrac{32-3}{6}\}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[8-\dfrac{29}{6}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-[\dfrac{48-29}{6}]\\\\=(\dfrac{1}{2}+ \dfrac{1}{3}) \div (\dfrac{1}{4}-\dfrac{1}{6})-\dfrac{19}{6}\\\\=(\dfrac{3+2}{6}) \div (\dfrac{3-2}{12})-\dfrac{19}{6}\\\\=(\dfrac{5}{6}) \div (\dfrac{1}{12})-\dfrac{19}{6}$

$=(\dfrac{5}{6}) * (\dfrac{12}{1})-\dfrac{19}{6}\\\\=10-\dfrac{19}{6}\\\\=\dfrac{60-19}{6}\\\\=\dfrac{41}{6}$