solve this question step by step plz
Answers
Step-by-step explanation:
Given :-
A bag contains 34 balls of which x are red ,2x are white and 3x are blue .A ball is selected from random.
To find :-
Find the probability that
i) it is not red
ii)it is either white or blue
iii)neither white nor blue
Solution :-
Total number of balls = 34
Number of red balls = x
Number of white balls = 2x
Number of blue balls = 3x
Since total number of balls = 34
=> x+2x+3x = 34
=> 6x = 34
=> x = 34/6
=> x = 5.6
Number of red balls 5.6 = 6
Number of white balls = 2×5.6 = 11.2 = 11
Number of blue balls = 3×5.6 = 16.8 = 17
Sample space = {red, white , blue balls}
=> n(S) = 6+11+17 = 34
A : Ball is not red
=> A = White + blue balls
=>n( A )= 11+17
=> n(A ) = 28
Probability of getting not a red ball = P(A)
=> P(A) = n(A) / n(S)
=> P(A) = 28/34
=> P(A) = 14/17
B : Ball is either white or blue
B = Blue balls + white balls
n(B) = 11+17
=> n(B) = 28
=> P(B) = n(B) / n(S)
=> P(B) = 28/34
=> P(B) = 14/17
C: Ball is neither blue nor white
=> C = Red balls
=> n(C) = 6
=> P(C) = n(C)/n(S)
=> P(C) = 6/34
=> P(C) = 3/17
Answer:-
I) The probability of getting anot a red ball = 14/17
II) The probability of getting either blue or white ball = 14/17
III) The probability of getting neither blue nor white ball = 3/17
Used formulae:-
Probability of an event P(E) = Number of all favourable outcomes/ Total number of all possible outcomes
=> P(E) = n(E)/n(S)