Question

solve this question
$(7 \div 3 \times 1 \div 28) + (3 \div 4 \times 5 \div 2) + ( - 1 \div3 \times 7 \div 8)$
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Answer 1

Answer:

$(7 \div 3 \times 1 \div 28) + (3 \div 4 \times 5 \div 2) + ( - 1 \div 3 \times 7 \div 8) \\ \\ = (7 \div 84) + (15 \div 8) + ( - 7 \div 24) \\ \\ = 7 \div 84 + 15 \div 8 - 7 \div 24 \\ \\ = 56 + 1260 \div 672 \\ \\ = 1316 \div 672 \\ \\ = 329 \div 168 - 7 \div 24 \\ \\ = 7896 - 1176 \div 4032 \\ \\ = 35 \div 21$