Question

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$\frac{1}{ \sqrt{3} + \sqrt{2} } - \frac{2}{ \sqrt{3} + \sqrt{5} } - \frac{3}{ \sqrt{5} + \sqrt{2} }$
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Answer 1

Answer:

Given

$\frac{ 1 }{ \sqrt{3} + \sqrt{2} } + \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} = \sqrt{3} - \sqrt{2} \\ \\ \frac{2}{ \sqrt{5} + \sqrt{3} } \times \frac{ \sqrt{5} - \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \\ = \frac{2( \sqrt{5} - \sqrt{3 }) }{5 - 3} = \sqrt{5} - \sqrt{3} \\ \\ \frac{3}{ \sqrt{5} + \sqrt{2} } \times \frac{ \sqrt{5} - \sqrt{2} }{ \sqrt{5} - \sqrt{2} } \\ = \frac{3( \sqrt{5} - \sqrt{2}) }{5 - 2} = \sqrt{5} - \sqrt{2}$

$\sqrt{3} - \sqrt{2} - \sqrt{5} + \sqrt{3} - \sqrt{5} + \sqrt{2} \\ 2( \sqrt{3} - \sqrt{5} )$

Answer 2

Answer:

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