solve this question, this is from the chapter arthemetic progression
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hope this help u.........
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srimayeeBandi:
it really helps
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let A1=3b-1
A2=3b+5
A3=5b+1
we know that in an AP thatthe common difference is always the same.
A2-A1=A3-A2
(3b+5)-(3b-1)=(5b+1)-(3b+5)
3b+5-3b+1=5b+1-3b-5
6=2b-4
10=2b
b=5
A2=3b+5
A3=5b+1
we know that in an AP thatthe common difference is always the same.
A2-A1=A3-A2
(3b+5)-(3b-1)=(5b+1)-(3b+5)
3b+5-3b+1=5b+1-3b-5
6=2b-4
10=2b
b=5
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