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In triangle ABC,
DE is parallel to AC,
therefore, by BPT,
BE/AC=AD/DB......(i)
BE/EC=BF/FC
In triangle ABE,
DF Iis parallel to AE, By BPT
BF/FE=AD/BD....(ii)
From (i)and (ii),
BF/FE=BE/EC
Therefore proved!!
Hope it helps you!!!!!
DE is parallel to AC,
therefore, by BPT,
BE/AC=AD/DB......(i)
BE/EC=BF/FC
In triangle ABE,
DF Iis parallel to AE, By BPT
BF/FE=AD/BD....(ii)
From (i)and (ii),
BF/FE=BE/EC
Therefore proved!!
Hope it helps you!!!!!
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