Question

solve this question urgent

Answer 1

Answer:

(A) As parallelogram ABCD and ABEF lie on same base and between same parallels , then

 ar (ABCD) =ar (ABEF)

(B) As ar (ABCD) =ar (ABEF) then,

 1/2ar (ABCD) =  1/2ar (ABEF)

ar(ABD) = 1/2 ar(ABCD) =  1/2ar (ABEF)

(C) ar(BEF) =  1/2ar (ABEF) = 1/2 ar(ABCD)