Question

solve this question using the algebraic identity
x^3 + y^3 + z^3

Answer 1

[0010001111]... Hello User... [1001010101]
Here's your answer...

This sum uses the identity...
If a+b+c = 0
then a³+b³+c³ = 3abc

Here,
$a = \frac{1}{3} \: \: \: b = \frac{1}{2} \: \: \: c = - \frac{5}{6} \\ a + b + c = 0 \\ so \: {( \frac{1}{3}) }^{3} + ( { \frac{1}{2} )}^{3} + ( - { \frac{5}{6} )}^{3} \\ = 3 \times \frac{1}{3} \times \frac{1}{2} \times ( - \frac{5}{6} ) \\ = - \frac{5}{12}$

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