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Given :BD divides the diognals AC in ratio 1:2
To Prove: Dc =2AB
Proof: in ∆AOB and ∆COD
angle OAB =angle OCD{Alternate angles are equal as AB||CD}
angle AOB =angle ODC{alternate angles are equal as AB|| CD}
Therefore,∆AOB= ∆COD by AAA similarity
Now as both the triangles are similar, we can say that,
AO/OC= AB/CD
AO/OC=1/2(given)
We can say that
AB /CD= 1/2
and therefore by multiplying CD= 2AB
Hence ,Proved
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