Question

Solve this question
with detailed explanation
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Answer 1

Final Answer : C
$\frac{1}{t} \times 2.303 log( \frac{2p( \infty )}{3(p( \infty ) - p(t))} )$

Steps and Understanding :

1) Since, all are gases and assuming they are ideal in nature.

By Ideal Gas equation, at constant temperature, we can say that ratio of concentration of reactant at two different time intervals is equal to ratio of its partial pressure at those same partial pressures.

2) Then, we will write the reaction along with their amount of pressure exerted at t =0 , t = t and t = inf.

Then, use amount of pressure given in question.

3 ) We will write pressure at t = 0 and t = t for reactant in terms of given pressures.

4 ) Then, we will use our First Order Equation .
k. =
$\frac{1}{t} \times 2.303 \times log( \frac{c(0)}{c(t)} )$
where C(0) is concentration of reactant at t = 0
and C (t) is concentration of reactant at t =t.

5) Then, we will just Replace these Concentration with partial pressure.

For Calculation see pic