Math, asked by tamatarsingh, 1 month ago

Solve this question with explanation​

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Answered by mohan1709
1

Step-by-step explanation:

hope it helps all the best

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anindyaadhikari13: Good approach used. Great!
Answered by Anonymous
2

Here, we will use simple concepts, which, just for the record, come under the name of Surds.

The question is a complete square root. However, the options don't consist of a square root sign on the whole expression. This hints that some kind of perfect square must be forming.

The solution goes like this:

\sqrt{2x^2-1+2x\sqrt{x^2-1}}

Here, we observe this: 2x\sqrt{x^2-1}

If a perfect square must be forming, this is a worthy middle term.

Basically, if we are getting something like \sqrt{a^2+2ab+b^2}, then this 2ab corresponds to 2x\sqrt{x^2-1}

Also, a little careful observation shows that if we compare 2x\sqrt{x^2-1} with 2ab, then there must also be the equivalent expressions of a^2 and b^2 in the original question.

And, this indeed is the case. Here's how:

 \sqrt{2x^2-1+2x\sqrt{x^2-1}}\\\\\\=\sqrt{x^2+x^2-1+2x\sqrt{x^2-1}}\\\\\\=\sqrt{(x)^2+2x\sqrt{x^2-1}+\left(\sqrt{x^2-1}\right)^2}\\\\\\\left[\quad\equiv\sqrt{a^2+2ab+b^2}\quad\right]\\\\\\=\sqrt{\left(x+\sqrt{x^2-1}\right)^2}\\\\\\=x+\sqrt{x^2-1}

And so we have:

 \boxed{\bold{\sqrt{2x^2-1+2x\sqrt{x^2-1}}=x+\sqrt{x^2-1}}}

Thus, The Answer is Option (2) \bold{x+\sqrt{x^2-1}}

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