Physics, asked by Anonymous, 10 months ago

✨✨Solve this question with full Solution ..........





✨✨What is the ratio of electric field intensity at a point on the equatorial line to the field at a point on axial line when the points are at the same distance from the centre of the dipole?

▪▪▪Don't spam........................ ​

Answers

Answered by Anonymous
1

Answer:

The ratio of the strength of an electric field at a point on axial line and a point on same distance at an equitorial line of an electric dipole of very small length is 2:1

- A force which would be exerted on other charged particles in a region around a charged particle object is called electric field

- The formula is given by equation,

E = 1 × 2P /4 πε0 r^3

- With the help of axial line of dipole the other two charges , i.e , positive and negative charges pass through it.

- The electric field at the axial line is equal to,

E(axial) = 1 × 2P /4 πε0 r^3

- The electric field at equatorial line is equal to,

E(equatorial)= 1 × P /4 πε0 r^3

- The ratio of the electric field intensity at the point on the equatorial line to the electric field at the point on axial line is,

- E(axial)/E(equatorial) =

1 × 2P /4 πε0 r^3/ 1 × P /4 πε0r^3

= 2/1

- *E(axial) : E(equatorial) = 2:1*


ritikyadav50: hlo
Anonymous: hola‼✌
ritikyadav50: did you have a twin sister
Anonymous: why?
ritikyadav50: no just asking
Answered by RJRishabh
1

HEYA ❤️

Here's your answer in the attachment .

Sorry for poor image quality.

Attachments:
Similar questions