Question

solve this question with full solutions




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Answer 1

Let the time taken by car A and car B be x seconds

Total distance covered by car A in x seconds = 10x m

So total distance covered by Car B(in order to chase the car) in x seconds = 10.5+ 10xm --(1)

As B "has to chase" Car A

Since the slope of velocity- time in Car is 45 degree then

tan 45 = 1

so final velocity and time is equal to xm/s

By the formula

S = ut+1/2 at^2

s = 10.5+10x m

u =0

a = v-u/t = x /x =1m/s

t = x second

10.5+10x = 0 × t + 1/2 × 1 × (x)^2

10.5 +10x = (x)^2/ 2

x^2 = 2(10.5+10x)

x^2 = 21+20x

x^2-20x-21 =0

By splitting middle term.

x^2 +x-21x-21 =0

( x-21 )(x+1) =0

x -21=0 and x+1 =0

x =21 x=-1

Since x can't be negative

THEREFORE TIME TAKEN IS 21 SECONDS

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