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Differentiate f(X)
f'(X) =
Now we take out the common terms
Now you can see that the critical points are
-1, 1 and 3
For X less than -1, we can see that f'(X) attains a negative value, hence slope there is negative.
By doing so further in the next interval of -1 to 1 we see that f'(X) is negative, hence slope there is also negative.
For 1 to 3 and 3 to infinity, slope is positive.
Hence from -∞ to -1, f(X) is decreasing while from -1 to ∞, f(X) is increasing.
f'(X) =
Now we take out the common terms
Now you can see that the critical points are
-1, 1 and 3
For X less than -1, we can see that f'(X) attains a negative value, hence slope there is negative.
By doing so further in the next interval of -1 to 1 we see that f'(X) is negative, hence slope there is also negative.
For 1 to 3 and 3 to infinity, slope is positive.
Hence from -∞ to -1, f(X) is decreasing while from -1 to ∞, f(X) is increasing.
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