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If 18 gm acetic acid dissolve 500ml water calculate the morality of solution molecular wt of Acetic acid is 60gm .
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answer is O.042M here solute is acetic acid (CH3COOH) and water is solvent we need to find molarity we know , Molarity-Moles of solute in gm/volume of solution in litres hence the moles of solute i.e. acetic acid = given mass /molar mass =1.26/60(molar mass of acetic acid is 60gm) =0.021 moles of acetic acid now 500ml =0.5 litres ,because the formula for molarity need volume of solution in litres putting values in formula, Molarity=0.021/0.5 =0.042 mol/litres
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