Question

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Answer 1

Answer:

Correct option is D)

Here, ma m 2 - -, mB = m

μA = 0.2, UB 0.1

Let both the blocks are moving with common acceleration a. Then,

From FBD of the block. a = = μAg = 0.2g = -

MA

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and F - MB (mB + mA)g (mB + MA)a

F = (m³ + mA)g + μ(m³ + mA)g

m =(m+)(0.2g) + (0.1) (m + m g

=(m)(0.2g) + (m)(0.1g) 0.9 2 -mg = 0.45mg

Explanation:

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