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Given,
- AB = AC.
- AD = AE.
Find,
- /_ADB = /_AEC.
- ▲ABD congruent to ▲ACE.
- BE = DC.
Solution,
In triangle ABC , we have
AB = AC.
so,/_ABC = /_ACB.
(By equal side opposite angle are equal) .
Now,
In triangles ABD / ACE.
AB = AC (Given) .
AD = AE (Given) .
/_ABC = /_ACB (proved above) .
Thus,
Triangles ABD / ACE are congruent by SAS congruence.
Therefore
/_ADB = /_AEC (By CPCT) .
and DB = EC (By CPCT) .
adding both sides DE.
DB+DE=EC+DE.
BE = DC.
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