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x/2=x/3+1
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⋆Case-1–––––––x∈(−∞,2)Hence in this interval |x-2|<0 and |x-3|<0Thus the equation becomes-⟹−(x−2)−(x−3)=1⟹−x+2−x+3=1⟹−2x=−4⟹x=2which is not possible as x<2Hence no possible solution from this interval
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