Solve this question.
xy(a²+1)+a(x²+y²)
Answers
Answered by
3
xy (a^2 +1) + a(x^2 + y^2)
= xya^2 + xy + ax^2 + ay^2
= xya^2 + ax^2 + ay^2 + xy
= ax (ay + x) + y (ay + x)
= (ay + x) (ax + y)
= xya^2 + xy + ax^2 + ay^2
= xya^2 + ax^2 + ay^2 + xy
= ax (ay + x) + y (ay + x)
= (ay + x) (ax + y)
Answered by
3
Answer :
Now,
xy (a² + 1) + a (x² + y²)
= a²xy + xy + ax² + ay²
= a²xy + ax² + xy + ay²
= ax (ay + x) + y (x + ay)
= ax (x + ay) + y (x + ay)
= (x + ay) (ax + y),
which is the required factorization.
#MarkAsBrainliest
Now,
xy (a² + 1) + a (x² + y²)
= a²xy + xy + ax² + ay²
= a²xy + ax² + xy + ay²
= ax (ay + x) + y (x + ay)
= ax (x + ay) + y (x + ay)
= (x + ay) (ax + y),
which is the required factorization.
#MarkAsBrainliest
Similar questions