Question

solve this questionn if you know

Answer 1

in triangle BCD
as CB = CD
it implies angle CBD = angleCDB
so angle CBD(also) = 40°
now in triangle BAD
AB = AD
so angle ABD = angle ADB = let x....
now using angle sum property in triangle ABD
sum of all angles = 180°
x + x + 110° = 180°
2x = 180 - 110
x = 70/2
x = 35°
it implies....
angle ABD = 35 °
SO....
(i)....angle ABC = angle ABD + angle CBD
angle ABC = 35 + 40 = 75°
(ii) in triangle BCD using angle sum property.....
angle CBD + angle CDB + angle BCD = 180°
40 + 40 + angle BCD = 180°
angle BCD = 180 - 80 = 80° .........
huh done.......hope it helps