Question

solve this questions ​

Answer 1

Step-by-step explanation:

$= > ({ \frac{9}{5}) }^{3} \times {( \frac{81}{25}) }^{3x} = { (\frac{9}{5} )}^{2x + 5}$

$= > ({ \frac{9}{5} })^{3} \times ({ \frac{9}{5} })^{6x} = ({ \frac{9}{5} )}^{2x + 5}$

$= > ({ \frac{9}{5} })^{6x + 3} = ( { \frac{9}{5} })^{2x + 5}$

$= >6x + 3 = 2x + 5$

$= > 6x - 2x = 5 - 3$

$= > 4x = 2$

$= > x = \frac{2}{4}$

$= > x = \frac{1}{2}$