Question

solve this questions​

Answer 1

Answer:

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Our zeros are 1 and -3.

For finding the quadratic polynomial,

Here, α=1, β=−3

Then, α+β=1+(−3)=−2

αβ=1×(−3)=−3

Sum of zeroes =α+β= −2

Product of zeroes =αβ= −3

Then, the quadratic polynomial = x²−( sum of zeroes ) x + product of zeroes

x² - ( -2 ) x + ( -3 )

= x² + 2x -3.

Verification:

Sum of zeroes =α+β= 1+(−3) = −2 or

Coefficient of x = 2

Coefficient of x = −1 = −2

Product of zeroes = αβ = (1) (−3) = −3 or

= Coefficient of x² = 1

Constant term = −3

1 × -3 = −3

So, the relationship between the zeroes and the coefficients is verified.

Answer 2

Step-by-step explanation:

let Alfa=1 and Bita= -3

Alfa+bita =1+(-3)=-2=-b/a

Alfa×Bita =1×(-3)=-3=c/a

therefore, a=1,b=2and c=-3

quadratic polynomial =x^2+2×-3

zero of the polynomial =1 and -3

-2=-b/a= cofficient of X/ cofficient x^2

-3= c/a = cofficient term/ cofficient of x^2