Math, asked by virendernegi1007, 2 days ago

solve this questions​

Attachments:

Answers

Answered by Rahul7895
1

Answer:

1)

\frac{1}{ \sqrt{5}  +  \sqrt{2} }  \\ =  \frac{1}{ \sqrt{5}  +  \sqrt{2} } \times  \frac{ \sqrt{5} -  \sqrt{2}  }{ \sqrt{5}   -  \sqrt{2} } \\  =  \frac{ \sqrt{5} -  \sqrt{2}  }{5 - 2}  \\  =  \frac{ \sqrt{5 }-  \sqrt{2} }{3} </p><p>

2)

 \frac{1}{ \sqrt{7} - 2 }  \\  =  \frac{1}{ \sqrt{7} - 2 } \times  \frac{ \sqrt{7}  + 2}{ \sqrt{7}  + 2}  \\  =  \frac{ \sqrt{7}  + 2}{ 7 - 4}  \\  =  \frac{ \sqrt{7} + 2 }{3}

Simplify

1)

 \frac{2 +  \sqrt{5} }{2 -  \sqrt{5} }  +  \frac{2 -  \sqrt{5} }{2 +  \sqrt{5} }  \\ </p><p> \frac{9 + 4 \sqrt{5}  + 9 -  4\sqrt{5} }{ - 1}  \\  =  \frac{18}{ - 1}  \\  =  - 18

hope it helps

Similar questions