Math, asked by riya42046, 11 months ago

solve this questions please​

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Answers

Answered by AmeyGodayal
1

Answer:

820 rupees

Step-by-step explanation:

so in the first month savings are 50 rupees and from the second month onwards it increases by 20 rupees, thus it makes 70 rupees. there are 12 months in a year and in the first month she saves 50 rps. hen second month  onwards there are 11 remaining months so 70 into 11 which is 770 along with the 50 rupees makes 820 rps thus she will not be able to send her daughter to school

Answered by Anonymous
0

SOLUTION

Let a be the first term and d be the common difference

We know that, sum of first n terms

 =  > sn =  \frac{n}{2} (2a + (n - 1)d)

A/q

Saving Ramkali in 1 year= Rs.50+ Rs.70+Rs. 90.......

Here,

a= 50

d= 70-50 = 20

n= 12

Therefore,

S12=) 12/2 [2×50+(12-1)20]

=) 6[100+220]

=) 6× 320

=) Rs.1920

Hence, After a year,she will save Rs.1920

Since, required amount for admission is Rs.1800 and her saving will be Rs.1920.

Thus,

Yes, she will be able to fulfill her dream of sending her daughter to school.

Hope it helps ✔️❣️

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