Question

solve this questions please​

Answer 1

Answer:

hope it helps

please mark as brainliest

Answer 2

DIAGRAM:

$\setlength{\unitlength}{1 mm}\begin{picture}(0,0)\put(30,-2){ \tt{22\:m} }\put(-16,-2){ \tt{18\:m} }\put(13,-14){ \tt{a} }\put(13,10){ \tt{b} }\put(2,-2){ \tt{H =16\: m} }\put(-5,6){ \tt{D} }\put(28,6){ \tt{C} }\put(-12,-8){ \tt{A} }\put(31,-8){ \tt{B} }\put(1,8){\line(0,-6){17}}\put(30.3,-8.8){\line(-4,0){39.5}}\put(26,8){\line(1,-4){4.2}}\put(1,8){\line(8,0){25}}\put(1,8){\line(-2,-13){10}}\end{picture}$

GIVEN:

• Perimeter of trapezium = 104m

• Altitude of trapezium = 16m

• AD and BC are non parallel sides .

• AD = 18m and BC = 22m

TO FIND:

• Area of trapezium (ABCD)

SOLUTION:

Perimeter of trapezium = 104m

=> AB + BC + CD + AD = 104m

=> a + 22 + b + 18 = 104m

=> a + b + 22 + 18 = 104m

=> a + b + 64 = 104m

=> a + b = 104 - 64

=> a + b = 64

=> a + b = 64m

Area of trapezium = 1/2 (a+b) × h

= 1/2 (a+b) × h

= 1/2 (64) × 16

= 1024/2

= 512

= 512 m²

Therefore,Area of trapezium is 512 m²