Question

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FIND THE AREA OF THE TRIANGLE WITH SIDES 35 CM, 54 CM AND 61 CM.​

Answer 1

Answer:

semiperimeter=(35+54+61)÷2

= 150÷2

=75 cm

using heron theory

$\sqrt{s(s - a)(s - b)(s - c)}$

=/75 (75-35)(75-54)(75-61)

=/75 (40)(21)(14)

=/5×13×2×2×2×5×3×7×7×2

=140/39cm^2

/stands for square root