Question

solve this questuon.​

Answer 1

$\frac{3}{ \sqrt{3} + 1 } + \frac{5}{ \sqrt{3} + 1 } \\ \frac{3 + 5}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{ 3} - 1} \\ \frac{8( \sqrt{3} - 1)}{ { (\sqrt{3}) }^{2} - {1}^{2} } \\ \frac{8( \sqrt{ 3} - 1) }{3 - 1} \\ \frac{8( \sqrt{3} - 1) }{2} \\ 4 \sqrt{3} - 4 = - 4 + 4 \sqrt{3} \\ a = - 4 \: \: \: \: b = 4 \sqrt{3}$