Question

solve This quick for getting 50 points each

Answer 1

conservation of energy - the kinetic energy of the system before the impact will be the same as the energy after

m1=10 m2=1 v1=5 v2=velocity of mass 1 after impact v3=velocity of mass 2 after impact

e = .5*m1*v1^2 =.5*10*5^2 = 125 kg-sec^2/m^2 = (.5*m1*v2^2) + (.5*m2*v3^2)

125= (5*v2^2) + (.5*v3^2)

Also, momentum must be conserved -

m1*v1 = 50 m/sec = m1*v2 + m2*v3 = 10*v2 + 1*v3

v3 = 50–10*v2 therefore v3^2 = 2500–1000*v2+100*v2^2

substituting v3^2 into the first equation

125 = 5*v2^2 +1250 - 500v2 + 50v2^2

0 = 55*v2^2 - 500*v2 + 1125

using the quadratic equation -

v2 = 5.00 or 4.09 and we know it can’t be 5.00

v2 = 4.09 v3 = 9.1

I think

Answer 2

⚫For these types of questions, consider applying the concept of:


$\sf{\underline{Conservation\:of\:momentum.}}$


⚫It states that:


If the system is isolated, and no external non conservative force acts on the system then, initial and final momentum of the system is conserved.


⚫For this we have to chose the system.

$\sf{\underline{As\:per\:your\:question,}}$


There are three possible systems.

=> The moving body.

=> The stationary body.

=> Both combined.