Solve this quick plz 7th question
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Given, root of 1+cos theta/1-cos theta can be written as
= root (1+cos theta)(1+cos theta)/(1-cos theta)(1+cos theta)
= root (1+cos theta)^2/sin^2 theta
= 1+cos theta/sin theta
= 1/sin theta + cos theta/sin theta
= cosec theta + cot theta.
Hope this helps!
= root (1+cos theta)(1+cos theta)/(1-cos theta)(1+cos theta)
= root (1+cos theta)^2/sin^2 theta
= 1+cos theta/sin theta
= 1/sin theta + cos theta/sin theta
= cosec theta + cot theta.
Hope this helps!
Answered by
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LHS=√1+cosA/1-cosA
rationalisation
=√(1+cosA)^2/1-cos^2A
=√(1+cosA)^2/sin^2A
=√(1+cosA/sinA)^2
=(1+cosA/sinA)
=1/sinA+cosA/sinA
=cosecA+cotA proved
rationalisation
=√(1+cosA)^2/1-cos^2A
=√(1+cosA)^2/sin^2A
=√(1+cosA/sinA)^2
=(1+cosA/sinA)
=1/sinA+cosA/sinA
=cosecA+cotA proved
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