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First Question answer=√2+√3+√5
Second Question Answer=0
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Solution 1:-
=> 10 + 2√6 + √60 + 2√10
Breaking the EQ to make the formula of (x + y+ z)²
( x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx
=> (x + y+ z)² = x² + y² + z² + 2( xy + yz + zx)
Breaking Seperately:-
10 = 5, 3, 2 = x² + y² + z²___________(1).
2√6 = 2xy
=> √6 = xy.__________________(2).
√60 = 2yz
=> 2√15 = 2yz
=> √15 = yz ___________________(3).
2√10 = 2xz
=> √10 = xz_____________________(4).
From EQ (1), (2), (3) & (4) the equation seems as the Formula of (x + y + z)²
=> ( x+y+z)² = x² + y² + z² + 2( xy + yz + zx).
Putting the values from all the above equations:
=> ( x² + y² + z²) + 2( xy + yz + zx)
=> ( √5² + √2² + √3²) + 2( √6 + √15 + √10)
=> ( √5 + √3 + √2)²
Hence,
The Positive Square Root is ( √5 , √3, √2).
Solution 2:-
Refer to the Attachment!!
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pratyush4211:
Thanks
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