solve this quickly with the process
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net force =100n
total mass=50kg
net a =100/50=2
fx=f-f(c)=> f-ma=f(c)=>100-40=60n
contact force = force(main)-mass(1)*acceleration.
one more way
fx=f(c) for the second block
m(2)a=f(c)
30*2=f(c)
60n=f(c)
hope I have helped you!!!
total mass=50kg
net a =100/50=2
fx=f-f(c)=> f-ma=f(c)=>100-40=60n
contact force = force(main)-mass(1)*acceleration.
one more way
fx=f(c) for the second block
m(2)a=f(c)
30*2=f(c)
60n=f(c)
hope I have helped you!!!
ManavSenguptaDPS:
wait,.....contact force is wrong
contact force value kya hoga
wait checking....
value is given 60
Newton
will u plz tell fast
i m getting late
friend it is a bit tricky...let me first see the process
ok
this one is 100% right
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