Question

Solve this!!
refer to above attachment​

Answer 1

Explanation:

Let in trapezium PQCD parallel sides are

QC=9x cm and PD =8x cm

it is given that are of trapezium PQCD

5/6×( area of rectangle ABCD)

1/2( PD+QC)× CD =5/6×(BC×CD)

1/2 (8X +9X) ×25=5/6×51×25

1/2×17X 25=5/6×51×25

X= 5×51×25×2/25×17×6 =>X=5

QC=(9×5)=45cm

PD=(8×5)=40cm

Answer 2

Explanation:

Area of m = Sur of opposite sides

* Height 2

Given:

PD = 8/9 * Q * C

Area of trapezium =(PD+QC) DC 2 = 17*25 18 QC

Area of gle = 25 * 51

Now given that Area of^ prime Area of (rapezium)/(Gamma*r * i * a * n * g * l * e) = 5/6

Area of ium = Su of opposite sides

* Height 2

Given:

PD = 8/9 * Q * C

Area of rapezium = (PD + QC) * (DC)/2 = (17 * 25)/18 * Q * C

Area of gle = 25 * 51

Feedback

Now given that Area of^ prime Area of (ipezium)/(ciangle) = 5/6

Therefore, ((17 * 25)/18 * Q * C)/(25 * 51) = 5/6

Therefore, Length of QC = 45

Therefore, 17*25 18 QC 18 25*51 = 5 6

Therefore, Length of QC = 45