Question

solve this right please ​

Answer 1

Answer:

(x+1)(x-1)

Step-by-step explanation:

There is an identity--->

(a+b)(a-b) = a^2 - b^2

Using this in our question---->

(x-2)(x+2) + 3

= x^2 - 2^2 +3

= x^2 - 4 + 3

= x^2 - 1

Now, 1 can be written as 1^2 also, so we can again use the same identity

x^2 - 1^2

= (x+1)(x-1)

Hope it helps :)

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Answer 2

$\bold{\LARGE{\underline{\underline{Answer:–}}}}$

$(x \: – \:2) \:(x \:+ \:2)\: +\:3\:\:=\:\:x²\: -\:1$

_____________________

$\bold{\LARGE{\underline{\underline{Explanation:–}}}}$

Factories :

$(x \: – \:2) \:(x \:+ \:2)\: +\:3$

.

Using identity:

$a\:+\:b)\:(a\: -\:b)\:=\:a²\: -\:b²$

Now,

$(x \: – \:2) \:(x \:+ \:2)\: +\:3$

$\Longrightarrow\:\:(x)²\: -\:(2)²\:+\:3$

$\Longrightarrow\:\:x²\: -\:4\:+\:3$

$\Longrightarrow\:\:x²\: -\:1$

.

So, $(x \: – \:2) \:(x \:+ \:2)\: +\:3\:\:=\:\:x²\: -\:1$