Question

solve this seris. 15,42,82,?,0,-1​

Answer 1

Given:

15, 42, 82, ?, 0, -1​

To find:

solve the given series

Solution:

The given series is 15, 42, 82, ?, 0, -1​

• Observe the given series carefully. we need to find the number in place of the question mark.

Let's find out how the series is formed.

$15 \times 3 - 3= 42$

$42 \times 2 - 2 = 82$

$82 \times 1 - 1 = 81$ (The required number is 81)

$81 \times 0 - 0 = 0$

$0 \times (-1) -1 = -1$

So, the series will be: 15, 42, 82, 81, 0, -1​

Hence, the required answer is 81

Answer 2

Given:

• 15, 42, 82, ?, 0, -1

To find:

• solve the given series

Solution:

• The given series is 15, 42, 82, ?, 0, -1

Observe the given series carefully. we need to find the number in place of the question mark.Let's find out how the series is formed.

$\\ \\ \\ 15 \times 3 - 3 = 4215 \times 3 - 3 = 42$

$\\ \\ 42 \times 2 - 2 = 82$

$\\ \\ 82 \times 1 - 1 = 81( \: \: required \: no \: is \: 81)$

$\\ \\ 81 \times 0 - 0 = 0$

$\\ \\ 0 \times ( - 1) - 1 = - 1$

So, the series will be: 15, 42, 82, 81, 0, -1

Hence, the required answer is 81