Solve this .Show necessary calculations
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Anonymous:
so nice handwriting!!
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(49)^{ 1 - log(2base 7) } + 5^{ - log(4 base 5) }
we know,
a^log( b base a } = b
use this concept here ,
= (49)^{ log( 7 base 7) - log(2 base 7)} + 5^log{(4)^-1 base 5 }
= (7²)^log{ (7/2) base 7 } + (4)^-1
= (7)^log{ (7/2)² base 7 } + 1/4
= (7/2)² + 1/4
=49/4 + 1/4
= 50/4
=25/2 ( answer )
=25/2
we know,
a^log( b base a } = b
use this concept here ,
= (49)^{ log( 7 base 7) - log(2 base 7)} + 5^log{(4)^-1 base 5 }
= (7²)^log{ (7/2) base 7 } + (4)^-1
= (7)^log{ (7/2)² base 7 } + 1/4
= (7/2)² + 1/4
=49/4 + 1/4
= 50/4
=25/2 ( answer )
=25/2
i hope this will correct
:-)
ya
the handwriting of the questioner is too good..
Answered by
1
Hey, Sis!
Can we be friends?
Have a great day ahead....!
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