Solve this simple equation by evaluating it operation and find the value x?
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ln(2x+√6)² = 0
=> 2log(2x+√6)=0
=> log(2x+√6) = 0
=> log(2x+√6) = log1
=> 2x+√6=1
=> 2x = 1-√6
=> x = (1-√6)/2
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