Question

solve this simple quistion​

Answer 1

Answer:

$\frac{ \sqrt{3} - 2 }{2}$

Step-by-step explanation:

$\sin30° = \frac{1}{2} \\ \\ \tan 60° = \sqrt{3} \\ \\ \cos 60° = \frac{1}{2} \\ \\ \sec 30° = \frac{2}{ \sqrt{3} }$

$= > 2 { \sin}^{2} 30° \tan 60° - 3 { \cos}^{2} 60° {\sec}^{2} 30° \\ \\ = > 2 \times {( \frac{1}{2} )}^{2} \times ( \sqrt{3} ) - 3 \times {( \frac{1}{2}) }^{2} \times {( \frac{2}{ \sqrt{3} } )}^{2} \\ \\ = > 2 \times \frac{1}{4} \times \sqrt{3} - 3 \times \frac{1}{4} \times \frac{4}{3} \\ \\ = > \frac{ \sqrt{3} }{2} - 1 \\ \\ = > \frac{ \sqrt{3} }{2} - 1 \times \frac{2}{2} \\ \\ = > \frac{ \sqrt{3} }{2} - \frac{2}{2} \\ \\ = > \frac{ \sqrt{3 } - 2}{2}$