Question

solve this simultaneous equation by substitution method 5a + 4c =108 / 2a + 3c =53​

Answer 1

MARK AS BRAIN LIST PLZZZZZ

Answer 2

The given equations are ,

$5a + 4c = 108 \\ 2a + 3c = 53$

Using substitution method ,

$5a = 108 - 4c \\ a = \frac{108 - 4c}{5}$

Substituting the value of a in equation 2 we get ,

$= > \frac{2(108 - 5c)}{4} + 3c = 53$

$= > 216 + 14c = 424$

$= > \frac{216 - 10c}{8} + 3c = 53$

$= > \frac{216 - 10c + 24}{8} = 53$

$= > 14c = 208 \\ = > c = \frac{208}{14}$

$c = 14.85$

Again substuting the value of c=14.85 in equation one we get,

$5a + 4c = 108 \\ 5a + 4(14.85) = 108 \\ = > 5a = 108 - 59.28 \\ = > a = \frac{48.72}{5} \\ = > a = 9.74$

Therefore the value of a=9.74

and b=14.85.