Question

Solve this simultaneous equation please

Answer 1

Answer:

x = 3

y = 1/2

Step-by-step explanation:

Let 1/y = a

4x + 3a = 18  -----i

3x + 2a = 13   ----ii

multiply i and ii by 2 and 3

8x + 6a = 36

9x + 6a = 39

-x = -3

x = 3

Put x in i

12 + 3a = 18

3a = 6

a = 2

also

a= 1/y

y = 1/2

Hope it will help you.........

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Answer 2

Answer:

Step-by-step explanation:

4 x+3/y=18⇒C

3 x+2/y=13

let 1/y=z

4 x+3 z=18⇒A

3 x+2 z=13⇒B

multiply A by 2 and B by 3

8 x+6 z=36

9 x+6 z=39     (BY ELIMINATION METHOD)

-        -      -

⇒ - x=-3

⇒x=3

put x=3 in A

4 (3)+3 z=18

12+3 z=18

3 z=18-12

3 z=6

z=2

as z=1/y

so, y=1/2

put  the value of y in C

4 x+3/1/2=18

4 x+6=18

4 x=12

x=3